Example - Emptying a Subpartition v13

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The example that follows removes the data from a subpartition of the sales table. Use the following command to create the sales table:

CREATE TABLE sales
(
  dept_no     number,
  part_no     varchar2,
  country     varchar2(20),
  date        date,
  amount      number
)
PARTITION BY RANGE(date) SUBPARTITION BY LIST (country)
(
  PARTITION "2011" VALUES LESS THAN('01-JAN-2012')
  (
    SUBPARTITION europe_2011 VALUES ('ITALY', 'FRANCE'),
    SUBPARTITION asia_2011 VALUES ('PAKISTAN', 'INDIA'),
    SUBPARTITION americas_2011 VALUES ('US', 'CANADA')
  ),
  PARTITION "2012" VALUES LESS THAN('01-JAN-2013')
  (
    SUBPARTITION europe_2012 VALUES ('ITALY', 'FRANCE'),
    SUBPARTITION asia_2012 VALUES ('PAKISTAN', 'INDIA'),
    SUBPARTITION americas_2012 VALUES ('US', 'CANADA')
  ),
  PARTITION "2013" VALUES LESS THAN('01-JAN-2015')
  (
    SUBPARTITION europe_2013 VALUES ('ITALY', 'FRANCE'),
    SUBPARTITION asia_2013 VALUES ('PAKISTAN', 'INDIA'),
    SUBPARTITION americas_2013 VALUES ('US', 'CANADA')
  )
);

Populate the sales table with the command:

INSERT INTO sales VALUES
  (10, '4519b', 'FRANCE', '17-Jan-2011', '45000'),
  (20, '3788a', 'INDIA', '01-Mar-2012', '75000'),
  (40, '9519b', 'US', '12-Apr-2012', '145000'),
  (20, '3788a', 'PAKISTAN', '04-Jun-2012', '37500'),
  (40, '4577b', 'US', '11-Nov-2012', '25000'),
  (30, '7588b', 'CANADA', '14-Dec-2011', '50000'),
  (30, '4519b', 'CANADA', '08-Apr-2012', '120000'),
  (40, '3788a', 'US', '12-May-2011', '4950'),
  (20, '3788a', 'US', '04-Apr-2012', '37500'),
  (40, '4577b', 'INDIA', '11-Jun-2011', '25000'),
  (10, '9519b', 'ITALY', '07-Jul-2012', '15000'),
  (20, '4519b', 'INDIA', '2-Dec-2012', '5090');

Querying the sales table shows that the rows have been distributed amongst the subpartitions.

edb=# SELECT tableoid::regclass, * FROM sales;
    tableoid       | dept_no| part_no | country|        date        | amount
-------------------+--------+---------+--------+--------------------+--------
sales_americas_2011|      30| 7588b   | CANADA | 14-DEC-11 00:00:00 | 50000
sales_americas_2011|      40| 3788a   | US     | 12-MAY-11 00:00:00 | 4950
sales_europe_2011  |      10| 4519b   | FRANCE | 17-JAN-11 00:00:00 | 45000
sales_asia_2011    |      40| 4577b   | INDIA  | 11-JUN-11 00:00:00 | 25000
sales_americas_2012|      40| 9519b   | US     | 12-APR-12 00:00:00 |145000
sales_americas_2012|      40| 4577b   | US     | 11-NOV-12 00:00:00 | 25000
sales_americas_2012|      30| 4519b   | CANADA | 08-APR-12 00:00:00 |120000
sales_americas_2012|      20| 3788a   | US     | 04-APR-12 00:00:00 | 37500
sales_europe_2012  |      10| 9519b   | ITALY  | 07-JUL-12 00:00:00 | 15000
sales_asia_2012    |      20| 3788a   | INDIA  | 01-MAR-12 00:00:00 | 75000
sales_asia_2012    |      20| 3788a   |PAKISTAN| 04-JUN-12 00:00:00 | 37500
sales_asia_2012    |      20| 4519b   | INDIA  | 02-DEC-12 00:00:00 | 5090
(12 rows)

To delete the contents of the 2012_americas partition, invoke the following command:

ALTER TABLE sales TRUNCATE SUBPARTITION "americas_2012";

Now, querying the sales table shows that the content of the americas_2012 partition has been removed.

edb=# SELECT tableoid::regclass, * FROM sales;
 tableoid          | dept_no| part_no | country  |        date        |amount
-------------------+--------+---------+----------+--------------------+------
sales_americas_2011|      30| 7588b   | CANADA   | 14-DEC-11 00:00:00 |50000
sales_americas_2011|      40| 3788a   | US       | 12-MAY-11 00:00:00 | 4950
sales_europe_2011  |      10| 4519b   | FRANCE   | 17-JAN-11 00:00:00 |45000
sales_asia_2011    |      40| 4577b   | INDIA    | 11-JUN-11 00:00:00 |25000
sales_europe_2012  |      10| 9519b   | ITALY    | 07-JUL-12 00:00:00 |15000
sales_asia_2012    |      20| 3788a   | INDIA    | 01-MAR-12 00:00:00 |75000
sales_asia_2012    |      20| 3788a   | PAKISTAN | 04-JUN-12 00:00:00 |37500
sales_asia_2012    |      20| 4519b   | INDIA    | 02-DEC-12 00:00:00 | 5090
(8 rows)

While the rows have been removed, the structure of the 2012_americas partition is still intact.

edb=# SELECT subpartition_name, high_value FROM ALL_TAB_SUBPARTITIONS;
 subpartition_name |     high_value
-------------------+---------------------
 EUROPE_2011       | 'ITALY', 'FRANCE'
 ASIA_2011         | 'PAKISTAN', 'INDIA'
 AMERICAS_2011     | 'US', 'CANADA'
 EUROPE_2012       | 'ITALY', 'FRANCE'
 ASIA_2012         | 'PAKISTAN', 'INDIA'
 AMERICAS_2012     | 'US', 'CANADA'
 EUROPE_2013       | 'ITALY', 'FRANCE'
 ASIA_2013         | 'PAKISTAN', 'INDIA'
 AMERICAS_2013     | 'US', 'CANADA'
(9 rows)

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ALTER TABLE...TRUNCATE SUBPARTITION

Handling Stray Values in a LIST or RANGE Partitioned Table

Example - Emptying a Subpartition v13

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