Handling stray values in a LIST or RANGE partitioned table v14
A DEFAULT or MAXVALUE partition or subpartition captures any rows that don't meet the other partitioning rules defined for a table.
Defining a DEFAULT partition
A DEFAULT partition captures any rows that don't fit into any other partition in a LIST partitioned or subpartitioned table. If you don't include a DEFAULT rule, any row that doesn't match one of the values in the partitioning constraints causes an error. Each LIST partition or subpartition can have its own DEFAULT rule.
The syntax of a DEFAULT rule is:
PARTITION [<partition_name>] VALUES (DEFAULT)
Where partition_name specifies the name of the partition or subpartition that stores any rows that don't match the rules specified for other partitions.
You can create a list-partitioned table in which the server decides the partition for storing the data based on the value of the country column. In that case, if you attempt to add a row in which the value of the country column contains a value not listed in the rules, an error is reported:
edb=# INSERT INTO sales VALUES edb-# (40, '3000x', 'IRELAND', '01-Mar-2012', '45000'); ERROR: no partition of relation "sales_2012" found for row DETAIL: Partition key of the failing row contains (country) = (IRELAND).
This example creates such a table but adds a DEFAULT partition. The server stores any rows that don't match a value specified in the partitioning rules for europe, asia, or americas partitions in the others partition.
CREATE TABLE sales
(
dept_no number,
part_no varchar2,
country varchar2(20),
date date,
amount number
)
PARTITION BY LIST(country)
(
PARTITION europe VALUES('FRANCE', 'ITALY'),
PARTITION asia VALUES('INDIA', 'PAKISTAN'),
PARTITION americas VALUES('US', 'CANADA'),
PARTITION others VALUES (DEFAULT)
);To test the DEFAULT partition, add a row with a value in the country column that doesn't match one of the countries specified in the partitioning constraints:
INSERT INTO sales VALUES (40, '3000x', 'IRELAND', '01-Mar-2012', '45000');
Query the contents of the sales table to confirm that the previously rejected row is now stored in the sales_others partition:
edb=# SELECT tableoid::regclass, * FROM sales;
tableoid | dept_no | part_no | country | date | amount
----------------+---------+---------+----------+--------------------+--------
sales_americas | 40 | 9519b | US | 12-APR-12 00:00:00 | 145000
sales_americas | 40 | 4577b | US | 11-NOV-12 00:00:00 | 25000
sales_americas | 30 | 7588b | CANADA | 14-DEC-12 00:00:00 | 50000
sales_americas | 30 | 9519b | CANADA | 01-FEB-12 00:00:00 | 75000
sales_americas | 30 | 4519b | CANADA | 08-APR-12 00:00:00 | 120000
sales_americas | 40 | 3788a | US | 12-MAY-12 00:00:00 | 4950
sales_americas | 40 | 4788a | US | 23-SEP-12 00:00:00 | 4950
sales_americas | 40 | 4788b | US | 09-OCT-12 00:00:00 | 15000
sales_europe | 10 | 4519b | FRANCE | 17-JAN-12 00:00:00 | 45000
sales_europe | 10 | 9519b | ITALY | 07-JUL-12 00:00:00 | 15000
sales_europe | 10 | 9519a | FRANCE | 18-AUG-12 00:00:00 | 650000
sales_europe | 10 | 9519b | FRANCE | 18-AUG-12 00:00:00 | 650000
sales_asia | 20 | 3788a | INDIA | 01-MAR-12 00:00:00 | 75000
sales_asia | 20 | 3788a | PAKISTAN | 04-JUN-12 00:00:00 | 37500
sales_asia | 20 | 3788b | INDIA | 21-SEP-12 00:00:00 | 5090
sales_asia | 20 | 4519a | INDIA | 18-OCT-12 00:00:00 | 650000
sales_asia | 20 | 4519b | INDIA | 02-DEC-12 00:00:00 | 5090
sales_others | 40 | 3000x | IRELAND | 01-MAR-12 00:00:00 | 45000
(18 rows)EDB Postgres Advanced Server provides the following methods to reassign the contents of a DEFAULT partition or subpartition:
- You can use the
ALTER TABLE… ADD PARTITIONcommand to add a partition to a table with aDEFAULTrule. There can't be conflicting values between existing rows in the table and the values of the partition you're adding. You can alternatively use theALTER TABLE… SPLIT PARTITIONcommand to split an existing partition. - You can use the
ALTER TABLE… ADD SUBPARTITIONcommand to add a subpartition to a table with aDEFAULTrule. There can't be conflicting values between existing rows in the table and the values of the subpartition you're adding. You can alternatively use theALTER TABLE… SPLIT SUBPARTITIONcommand to split an existing subpartition.
Example: Adding a partition to a table with a DEFAULT partition
This example uses the ALTER TABLE... ADD PARTITION command. It assumes there's no conflicting values between the existing rows in the table and the values of the partition to add.
edb=# ALTER TABLE sales ADD PARTITION africa values ('SOUTH AFRICA', 'KENYA');
ALTER TABLEWhen the following rows are inserted into the table, an error occurs, indicating that there are conflicting values:
edb=# INSERT INTO sales (dept_no, country) VALUES (1,'FRANCE'),(2,'INDIA'),(3,'US'),(4,'SOUTH AFRICA'),(5,'NEPAL'); INSERT 0 5
Row (4,'SOUTH AFRICA') conflicts with the VALUES list in the ALTER TABLE... ADD PARTITION statement, thus resulting in an error:
edb=# ALTER TABLE sales ADD PARTITION africa values ('SOUTH AFRICA', 'KENYA');
ERROR: updated partition constraint for default partition "sales_others"
would be violated by some rowExample: Splitting a DEFAULT partition
This example splits a DEFAULT partition, redistributing the partition's content between two new partitions in the table sales.
This command inserts rows into the table, including rows into the DEFAULT partition:
INSERT INTO sales VALUES (10, '4519b', 'FRANCE', '17-Jan-2012', '45000'), (10, '9519b', 'ITALY', '07-Jul-2012', '15000'), (20, '3788a', 'INDIA', '01-Mar-2012', '75000'), (20, '3788a', 'PAKISTAN', '04-Jun-2012', '37500'), (30, '9519b', 'US', '12-Apr-2012', '145000'), (30, '7588b', 'CANADA', '14-Dec-2012', '50000'), (40, '4519b', 'SOUTH AFRICA', '08-Apr-2012', '120000'), (40, '4519b', 'KENYA', '08-Apr-2012', '120000'), (50, '3788a', 'CHINA', '12-May-2012', '4950');
The partitions include the DEFAULT others partition:
edb=# SELECT partition_name, high_value FROM ALL_TAB_PARTITIONS; partition_name | high_value ----------------+--------------------- EUROPE | 'FRANCE', 'ITALY' ASIA | 'INDIA', 'PAKISTAN' AMERICAS | 'US', 'CANADA' OTHERS | DEFAULT (4 rows)
This command shows the rows distributed among the partitions:
edb=# SELECT tableoid::regclass, * FROM sales; tableoid | dept_no| part_no | country | date | amount --------------+--------+---------+--------------+--------------------+------- sales_americas| 30 | 9519b | US | 12-APR-12 00:00:00 |145000 sales_americas| 30 | 7588b | CANADA | 14-DEC-12 00:00:00 | 50000 sales_europe | 10 | 4519b | FRANCE | 17-JAN-12 00:00:00 | 45000 sales_europe | 10 | 9519b | ITALY | 07-JUL-12 00:00:00 | 15000 sales_asia | 20 | 3788a | INDIA | 01-MAR-12 00:00:00 | 75000 sales_asia | 20 | 3788a | PAKISTAN | 04-JUN-12 00:00:00 | 37500 sales_others | 40 | 4519b | SOUTH AFRICA | 08-APR-12 00:00:00 |120000 sales_others | 40 | 4519b | KENYA | 08-APR-12 00:00:00 |120000 sales_others | 50 | 3788a | CHINA | 12-MAY-12 00:00:00 | 4950 (9 rows)
This command splits the DEFAULT others partition into partitions named africa and others:
ALTER TABLE sales SPLIT PARTITION others VALUES
('SOUTH AFRICA', 'KENYA')
INTO (PARTITION africa, PARTITION others);The partitions now include the africa partition along with the DEFAULT others partition:
edb=# SELECT partition_name, high_value FROM ALL_TAB_PARTITIONS; partition_name | high_value ----------------+------------------------- EUROPE | 'FRANCE', 'ITALY' ASIA | 'INDIA', 'PAKISTAN' AMERICAS | 'US', 'CANADA' AFRICA | 'SOUTH AFRICA', 'KENYA' OTHERS | DEFAULT (5 rows)
This command shows that the rows were redistributed across the new partitions:
edb=# SELECT tableoid::regclass, * FROM sales; tableoid |dept_no | part_no | country | date | amount ---------------+--------+---------+-------------+--------------------+------- sales_americas | 30 | 9519b | US | 12-APR-12 00:00:00 |145000 sales_americas | 30 | 7588b | CANADA | 14-DEC-12 00:00:00 | 50000 sales_europe | 10 | 4519b | FRANCE | 17-JAN-12 00:00:00 | 45000 sales_europe | 10 | 9519b | ITALY | 07-JUL-12 00:00:00 | 15000 sales_asia | 20 | 3788a | INDIA | 01-MAR-12 00:00:00 | 75000 sales_asia | 20 | 3788a | PAKISTAN | 04-JUN-12 00:00:00 | 37500 sales_africa | 40 | 4519b | SOUTH AFRICA| 08-APR-12 00:00:00 |120000 sales_africa | 40 | 4519b | KENYA | 08-APR-12 00:00:00 |120000 sales_others_1 | 50 | 3788a | CHINA | 12-MAY-12 00:00:00 | 4950 (9 rows)
Defining a MAXVALUE partition
A MAXVALUE partition or subpartition captures any rows that don't fit into any other partition in a range-partitioned or subpartitioned table. If you don't include a MAXVALUE rule, any row that exceeds the maximum limit specified by the partitioning rules causes in an error. Each partition or subpartition can have its own MAXVALUE partition.
The syntax of a MAXVALUE rule is:
PARTITION [<partition_name>] VALUES LESS THAN (MAXVALUE)
Where partition_name specifies the name of the partition that stores any rows that don't match the rules specified for other partitions.
The last example created a range-partitioned table in which the data was partitioned based on the value of the date column. If you attempt to add a row with a date value that exceeds a date listed in the partitioning constraints, EDB Postgres Advanced Server reports an error.
edb=# INSERT INTO sales VALUES edb-# (40, '3000x', 'IRELAND', '01-Mar-2013', '45000'); ERROR: no partition of relation "sales" found for row DETAIL: Partition key of the failing row contains (date) = (01-MAR-13 00:00:00).
This CREATE TABLE command creates the same table but with a MAXVALUE partition. Instead of throwing an error, the server stores any rows that don't match the previous partitioning constraints in the others partition.
CREATE TABLE sales
(
dept_no number,
part_no varchar2,
country varchar2(20),
date date,
amount number
)
PARTITION BY RANGE(date)
(
PARTITION q1_2012 VALUES LESS THAN('2012-Apr-01'),
PARTITION q2_2012 VALUES LESS THAN('2012-Jul-01'),
PARTITION q3_2012 VALUES LESS THAN('2012-Oct-01'),
PARTITION q4_2012 VALUES LESS THAN('2013-Jan-01'),
PARTITION others VALUES LESS THAN (MAXVALUE)
);To test the MAXVALUE partition, add a row with a value in the date column that exceeds the last date value listed in a partitioning rule. The server stores the row in the others partition.
INSERT INTO sales VALUES (40, '3000x', 'IRELAND', '01-Mar-2013', '45000');
Query the contents of the sales table to confirm that the previously rejected row is now stored in the sales_others partition:
edb=# SELECT tableoid::regclass, * FROM sales; tableoid | dept_no | part_no | country | date | amount ---------------+---------+---------+----------+--------------------+-------- sales_q1_2012 | 10 | 4519b | FRANCE | 17-JAN-12 00:00:00 | 45000 sales_q1_2012 | 20 | 3788a | INDIA | 01-MAR-12 00:00:00 | 75000 sales_q1_2012 | 30 | 9519b | CANADA | 01-FEB-12 00:00:00 | 75000 sales_q2_2012 | 40 | 9519b | US | 12-APR-12 00:00:00 | 145000 sales_q2_2012 | 20 | 3788a | PAKISTAN | 04-JUN-12 00:00:00 | 37500 sales_q2_2012 | 30 | 4519b | CANADA | 08-APR-12 00:00:00 | 120000 sales_q2_2012 | 40 | 3788a | US | 12-MAY-12 00:00:00 | 4950 sales_q3_2012 | 10 | 9519b | ITALY | 07-JUL-12 00:00:00 | 15000 sales_q3_2012 | 10 | 9519a | FRANCE | 18-AUG-12 00:00:00 | 650000 sales_q3_2012 | 10 | 9519b | FRANCE | 18-AUG-12 00:00:00 | 650000 sales_q3_2012 | 20 | 3788b | INDIA | 21-SEP-12 00:00:00 | 5090 sales_q3_2012 | 40 | 4788a | US | 23-SEP-12 00:00:00 | 4950 sales_q4_2012 | 40 | 4577b | US | 11-NOV-12 00:00:00 | 25000 sales_q4_2012 | 30 | 7588b | CANADA | 14-DEC-12 00:00:00 | 50000 sales_q4_2012 | 40 | 4788b | US | 09-OCT-12 00:00:00 | 15000 sales_q4_2012 | 20 | 4519a | INDIA | 18-OCT-12 00:00:00 | 650000 sales_q4_2012 | 20 | 4519b | INDIA | 02-DEC-12 00:00:00 | 5090 sales_others | 40 | 3000x | IRELAND | 01-MAR-13 00:00:00 | 45000 (18 rows)
EDB Postgres Advanced Server doesn't have a way to reassign the contents of a MAXVALUE partition or subpartition.
- You can't use the
ALTER TABLE… ADD PARTITIONstatement to add a partition to a table with aMAXVALUErule. However, you can use theALTER TABLE… SPLIT PARTITIONstatement to split an existing partition. - You can't use the
ALTER TABLE… ADD SUBPARTITIONstatement to add a subpartition to a table with aMAXVALUErule. However, you can split an existing subpartition with theALTER TABLE… SPLIT SUBPARTITIONstatement.